Friday 6 November 2015

Advance Vedic Maths Subtraction Technique


Advance Vedic Maths Subtraction Technique

In our previous post we had seen basic vedic mathematics technique to subtract numbers. Today we will see advance binary subtraction technique which can be applied to any general subtraction. This is quite faster technique than the traditional one which we have learned in our schools and with this method you don’t have to worry about the borrow as well.
In this method two vedic maths sutras( formula) are used

1. All from 9 and last from 10 ( निखिलं नवतश्चरमं दशतः)
 
2. By one more than one before (एकाधिकेन पूर्वेण )
We have used the first formula in our basic binary subtraction technique. The second one mentioned above is also simple. By one more than one before simply means increasing previous digit by one. For example one more than 4 is 5 , one more than 56 is 57 and like wise.

Let us understand the steps involved in this subtraction technique by solving 3895- 1926

Step 1: Start with the right most digit. If the top digit is smaller than the bottom digit then,  take the complement of the bottom digit and add it to the top digit this will be our answer digit and increase the next digit by one by putting a dot on it.

As we can observe that the top digit 5 is smaller than the bottom digit 6 , so 6 cannot be subtracted from 5, so we take the complement of 6 which is 4 and add it to the top digit 5, to get 9  (5+4 )as the unit digit answer. Then we apply the one more than one before concept and increase the previous digit by one by putting a dot. So 2 will now be treated as 3

Step 2: In the ten’s place upper digit in 9 and lower digit is 3 ( 2 is now 3 ) . 3 can be directly subtracted from 9 to get 6

Step 3. At the 100th place upper digit in 8 and lower digit is 9 , as 9 cannot be subtracted from 8 we will find the complement of 9 which is 1 and add it to 8 to get 9 as the 100th place answer. Then we place a dot over the next lower digit 1 to make it 2

Step 4.  1 is now 2 and it can be directly subtracted from 3 to get 1 as the thousand place answer digit.
As you can see in this method there is no headache of borrow like in the traditional method. With practice you can do it very fast and even mentally.   Below are some solved problems for your reference on this method.

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