Multiplication of two 2 digit numbers in maths it's an cool mathematics trick

Multiplication of two 2 digit numbers in maths

This is based on a sutra called Urdhva tiryagbhyam on vedic mathematics. With this method any no of digits can be multiplied in a single line.

First we take a sample like 34 × 56

1. Multiply last digit of the 2 numbers.

3              4              (2 reminder)

5              6

____________

4

2. Multiply the 2 digits diagonally and add them.

3              4              (3 ×6) + (5×4) + 2 = 40 , Reminder 4

5              6

____________

04

3. Now multiply first digit of the 2 numbers.

3              4              (3 ×5) +  4 = 19

5              6

____________

1904   

67 × 29

6              7              ((7×9), ((6×9)+(2×7)), (6×2))

2              9

____________

      1943

There is a cool maths trick.

2. Digit  Multiplication by 11 is very easy . You just need to add that 2 digits together and put that sum in between them. easy.. isn’t it! lets check.. for 26 ×11  , add 2 + 6  and  put 8 in between that 2 and 6. its 286!  if you get more than 9, just add the reminder to the first digit. try  95 × 11,  while placing 14 between 9 and 5, we have to add the 1 to 9. finally we got 1049.

For multiplying any digit number with 12, we have to  double each digit and add its neighbor.

43 ×12

Double of the first 3 ( 6) would be the last digit of result. then we have to add double of the next digit 4 (8) and add its neighbor 3 ( 11) and put 1 and keep the other 1 as reminder. for adding up the last digit, we have to assume a zero before 4 and doubling it will not give any result(0). So finally we have to add that 0 to the neighbor 4 and reminder 1, we will get 5. So the result is 516.

The Trick is for multiplying any number by 11 to 19  , we have to follow the common formula, instead of doubling the digit, multiply with no of times  equal to the last digit of 11 to 19 series and adding to the neighbor. Is it Confusing?

Lets say if you want to multiply a number by 13, we have to multiply the each digit by 3 and add it to the neighbor.

43 ×13 

3 ×3 = 9 So First Digit would be 9

4 × 3 =12 + neighbor 3 = 15, Next Digit would be 5

0 × 3 = 0 + neighbor 4 +reminder 1 = 5, SO its 559.

43 ×14 

3 ×4 = 12 So First Digit would be 2

4 × 4 =16 + neighbor 3 +reminder 1  = 20, Next Digit would be 0

0 × 4 = 0 + neighbor 4 +reminder 2 = 6, SO its 602

43 ×15 

3 ×5 = 15 So First Digit would be 5

4 × 5 =20 + neighbor 3 +reminder 1  = 24, Next Digit would be 4

0 × 4 = 0 + neighbor 4 +reminder 2 = 6, SO its 645